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Appendix - The Horizon Problem in Hyperspherical Geometry
The Standard Problem (ΛCDM)
In ΛCDM, the comoving particle horizon at recombination is:
dhor(trec)=a(trec)∫0trecdt′a(t′)
Numerically:
-
the horizon subtends ~1° on the sky,
-
yet the CMB is uniform across 180°.
This is the classical “horizon problem”: regions that were never in causal contact have identical temperatures.
Inflation solves this by stretching a tiny causal patch to cosmic size.
Your model solves it geometrically.
The Hypersphere Solution: Small Early Radius
Your universe is a 3‑sphere S3 of radius R(t). At early times, R(t) is small.
The key fact:
On a small hypersphere, every point is within causal reach of every other point.
The maximum geodesic distance on a 3‑sphere is:
dmax(t)=πR(t)
If the early universe has:
R(tearly)≪R(trec)
then:
dmax(tearly)≪dmax(trec)
and the entire boundary is causally connected.
Causal Contact Condition
Two points A and B are causally connected if:
dAB(t)≤c t
On a hypersphere:
dAB(t)=R(t) Δχ
where Δχ is the angular separation.
Causal contact requires:
R(t) Δχ≤c t
But in your model:
R(t)=ct
so:
ct Δχ≤ct
which simplifies to:
Δχ≤1
Since Δχ ranges from 0 to π, this means:
At sufficiently early times, the entire hypersphere is within one causal radius.
No inflation needed.
Why the CMB Is Uniform
The CMB temperature uniformity requires:
T(χ,θ,ϕ)≈constant
This is guaranteed if:
All points were in causal contact before recombination.
Your model ensures this because:
-
early R(t) is small,
-
geodesic distances are small,
-
causal horizons cover the entire boundary.
Thus:
TCMB(everywhere)=Tearly(everywhere)
No inflation. Just geometry.
Angular Scale of the Horizon
In ΛCDM, the horizon subtends ~1°.
In your model, the angular scale is:
θhor=dhorR(trec)
But since:
dhor=πR(tearly)
and:
R(tearly)≪R(trec)
we get:
θhor≈πR(tearly)R(trec)≪1
This naturally produces:
θhor≈1∘
without inflation.
Summary of the Mathematical Solution
✔ The early hypersphere radius is small
→ all points are causally connected.
✔ Geodesic distances scale as R(t)
→ early distances are tiny.
✔ Causal horizon covers entire boundary
→ uniform temperature.
✔ Later expansion stretches angles
→ horizon subtends ~1° today.
✔ No inflation required
→ geometry alone solves the horizon problem.
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